Draw a single loop that visits each white cell in the grid, and none of the black cells. The lines in the loop can only be vertical and horizontal. A clue next to a row or a column indicates the length of the longest straight part of the loop in that row or column. A length of a segment is the number of grid lines it crosses (imagine the loop is drawn between cell-centers, and one unit of length is the distance between the center of one cell and the center of its orthogonally neighboring cell).
Monday, April 5, 2021
Puzzle 176: Maximal Lengths
Saturday, April 3, 2021
Puzzle 175: Inversed LITS(O)
We define an orthogonally contiguous shape to be a shape in which there is a path between every two squares in it using only vertical and horizontal lines, and going only through squares that are part of the shape.
In each bordered area, shade some cells so that exactly 4 squares in that area remain unshaded -- those 4 squares must be orthogonally contiguous (a tetromino). No two identical unshaded tetrominoes (from different areas) can touch orthogonally (mirrors and rotations are considered identical); but they can touch diagonally -- that is, they cannot share an edge of a cell, but they can share a corner of a cell. After you are done, the shaded squares should form a single orthogonally contiguous shape, with no 2X2 squares in it.
The puzzle has a single solution.
-
I think this puzzle is somewhat complex, but very satisfying when you manage to solve it. אני חושבת שהחידה הזאת די מורכבת, אבל מאוד מספקת...
-
Fill in the grid with the numbers 1-5. Each number must appear exactly once in each row and in each column. There are two special cases we ...
-
Fill in the grid with the numbers 1-5, so that each number appears exactly once in each row and in each column. The numbers in the grid also...